An observer in reference frame S notes that two events areseparated in space by

Question

An observer in reference frame S notes that two events areseparated in space by 200 m and in time by 0.90 microseconds. How fast must reference frame S' be moving relative to Sin order for an observer in S' to detect the two events asoccurring at the same location in space? v=??m/s An observer in reference frame S notes that two events areseparated in space by 200 m and in time by 0.90 microseconds. How fast must reference frame S' be moving relative to Sin order for an observer in S' to detect the two events asoccurring at the same location in space? v=??m/s

Explanation / Answer

v=d/t and t u have to multiply by 10^-4 and then u get the answer

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