a circular plastic disk with radius R = 2.00 cm has auniformly distributed charg

Question

a circular plastic disk with radius R = 2.00 cm has auniformly distributed charge Q = + (2.00 x 106) e on oneface a circular ring of width 30 m is centred on that facewith the centre of that width at radius r = 0.50 cm in coulombswhat charge is contained with in the width of the ring In step 3, where is this coming from and the steps afterthat A'= (R~r)(R+r)    = dr(R-r+2r) Please show me all the steps becasue I m confuse on how thearea is being calculating. Thanks a circular plastic disk with radius R = 2.00 cm has auniformly distributed charge Q = + (2.00 x 106) e on oneface a circular ring of width 30 m is centred on that facewith the centre of that width at radius r = 0.50 cm in coulombswhat charge is contained with in the width of the ring In step 3, where is this coming from and the steps afterthat A'= (R~r)(R+r)    = dr(R-r+2r) Please show me all the steps becasue I m confuse on how thearea is being calculating. Thanks

Explanation / Answer

   from    dA = 2 r dr    dq = dA    so that we have    dq = (Q / R2) 2 rdr    where we have used the fact that the disk isunifirmly charged to set the surface charge density equal to thetotal charge    (Q) divided by the total area    next we set r = 0.0050 m and make theapproximation    dr = 30 x 10-6 m    so we get that    dq = 2.4 x 10-16 C

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