A 940g rock is whirled in a horizontal circle at the end of a1.2m long string (i

Question

A 940g rock is whirled in a horizontal circle at the end of a1.2m long string (info given) 1.?If the breaking strength of the string is 120N, what is themaxiumum allowable speed of the rock? 2.?At this maximum speed, what angle does the string make withthe horizontal? Comment, I am totally lost, my professor assiged this and wehaven't covered the chapter yet. A 940g rock is whirled in a horizontal circle at the end of a1.2m long string (info given) 1.?If the breaking strength of the string is 120N, what is themaxiumum allowable speed of the rock? 2.?At this maximum speed, what angle does the string make withthe horizontal? Comment, I am totally lost, my professor assiged this and wehaven't covered the chapter yet.

Explanation / Answer

mass, m = 940 X 10 -3 kg length of the string, l = 1.2 m Breaking strength = 120 N Centripetal force = Breaking strength             mv 2 / r = 120 ...............(1)    If = angle made by the string withhorizontal          and             T= tension in the string , then           T sin = mg            Tcos = m v 2 / r              Tan = rg / v 2 ............(2)            radius, r = l cos ...............(3) Solve the above expressions to find 'v' and ''

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