Two polarizers have their transmission axes perpendicular toeach other (they are

Question

Two polarizers have their transmission axes perpendicular toeach other (they are 'crosed'). Unploarized light ofirradiane I is incident on the first polarizer. The transmittedlight is then incident on the second polarizer. a) How much light is transmitted through both polarizers?(This answer does not require a calculation!) b) A third polarizer is inserted between the two polarizers.Its transmission axis is at an angle with respect to theirst polarizr. How much light is transmitted through the threepolarizers? Two polarizers have their transmission axes perpendicular toeach other (they are 'crosed'). Unploarized light ofirradiane I is incident on the first polarizer. The transmittedlight is then incident on the second polarizer. a) How much light is transmitted through both polarizers?(This answer does not require a calculation!) b) A third polarizer is inserted between the two polarizers.Its transmission axis is at an angle with respect to theirst polarizr. How much light is transmitted through the threepolarizers?

Explanation / Answer

Two polarizers have their transmission axes perpendicular toeach other (they are 'crosed'). Unploarized light ofirradiane I is incident on the first polarizer. The transmittedlight is then incident on the second polarizer. a) How much light is transmitted through both polarizers?(This answer does not require a calculation!)
ZERO
b) A third polarizer is inserted between the two polarizers.Its transmission axis is at an angle with respect to theFirst polarizr. How much light is transmitted through the threepolarizers?
after the second polarizer according to Malus law
I=Iocos2
again after the third one applying the same rule
I=[Iocos2]cos2(90-)
since cos(90-)=sin
we have
I=[Iocos2]sin2

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