Two ice skaters, Paul and Tom, are each holding on to oppositeends of the same r

Question

Two ice skaters, Paul and Tom, are each holding on to oppositeends of the same rope. Each pulls the other end towardhim. The magnitude of Paul's acceleration is 1.25 timesgreater than the magnitude of Tom's acceleration. What is theratio of Paul's mass to Tom's mass? The answer it 0.80... but I am not sure how the solutionmanual came up with this? I get that the magnitude of forces= mass * magnitude of acceleration, therefore,mpap=mtat butwhere does 0.80 come from? Two ice skaters, Paul and Tom, are each holding on to oppositeends of the same rope. Each pulls the other end towardhim. The magnitude of Paul's acceleration is 1.25 timesgreater than the magnitude of Tom's acceleration. What is theratio of Paul's mass to Tom's mass? The answer it 0.80... but I am not sure how the solutionmanual came up with this? I get that the magnitude of forces= mass * magnitude of acceleration, therefore,mpap=mtat butwhere does 0.80 come from?

Explanation / Answer

mpap=mtat The magnitude of Paul's acceleration is 1.25 times greaterthan the magnitude of Tom's acceleration. i.e., mp= 1.25 mt plug the value we get 1.25 mt *ap = mt*at                                     1.25 *ap = at                                            ap / at = 1/ 1.25                                                      = 0.8

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