A 100-kg log is pulled along a horizontal surface withfrictional force 300 N opp

Question

A 100-kg log is pulled along a horizontal surface withfrictional force 300 N opposing the motion. (a) If the applied is450-N, what is the acceleration? (b) if the acceleration is 2m/s^2, what is the applied force? Homework question i got wrong, the teacher did not explainwhich part of the problem i got wrong. He gave me the answer,without showing me the work. A 100-kg log is pulled along a horizontal surface withfrictional force 300 N opposing the motion. (a) If the applied is450-N, what is the acceleration? (b) if the acceleration is 2m/s^2, what is the applied force? Homework question i got wrong, the teacher did not explainwhich part of the problem i got wrong. He gave me the answer,without showing me the work.

Explanation / Answer

m = 100 kg Fr = 300 N a) F = 450 N         We can write          F - Fr =ma      a = (F - Fr )/ m            = (450 - 300 ) / 100            = 150 / 100 = 1.5 m/s2 b) applied force F = Fr + ma = 300 + 100 * 2 = 500N b) applied force F = Fr + ma = 300 + 100 * 2 = 500N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.