Hi, please, can you explain step by step. A rocket is fired vertically and ascen
ID: 1764222 • Letter: H
Question
Hi, please, can you explain step by step. A rocket is fired vertically and ascends with a constantvertical acceleration of 20 m/s2 for 1.0 min. Its fuel is then all used and it continues as a free-fallparticle. a. What is the maximum altitude reached? b. What is the total time elapsed from takeoff until therocket strikes the Earth? (Ignore the variation of g with altitude.) Thank you Hi, please, can you explain step by step. A rocket is fired vertically and ascends with a constantvertical acceleration of 20 m/s2 for 1.0 min. Its fuel is then all used and it continues as a free-fallparticle. a. What is the maximum altitude reached? b. What is the total time elapsed from takeoff until therocket strikes the Earth? (Ignore the variation of g with altitude.) Thank youExplanation / Answer
Accleration a = 20 m / s ^ 2 time t= 1min = 60 s velocity after time t is v = u + at = 0 + 20 * 60 = 1200 m / s distance nmoved in 1 min S = ut +( 1/ 2) at^2 = 0 + [ 0.5 * 20 * 60 ^ 2 ] = 36000 m height reached by rocket above height S is = v ^2/ 2g h= 73469.387 m So, maximum height above the ground H = S + h = 109469.387 m (b). time to reach maximum height after 1 min is t= v / g = 1200 / 9.8 = 122.44 s time taken to reach the rocket from height H to ground t' = [ 2H / g ] t ' = 149.46 s So, total time T = 1 min + t + t ' = 331.9 s (b). time to reach maximum height after 1 min is t= v / g = 1200 / 9.8 = 122.44 s time taken to reach the rocket from height H to ground t' = [ 2H / g ] t ' = 149.46 s So, total time T = 1 min + t + t ' = 331.9 sRelated Questions
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