A 0.5 kg rubber ball is dropped from a height of 3.0m above ahard concrete floor
ID: 1764458 • Letter: A
Question
A 0.5 kg rubber ball is dropped from a height of 3.0m above ahard concrete floor. After striking the floor the ball bounces upto a height of 2.0m above the floor. The ball was in contact withthe floor for 0.05s. A) Calculate the change in momentum (impulse) of the ballduring the interaction with the floor. B)Calculate the magnitude of the average force of the floor onthe ball during the interaction. A 0.5 kg rubber ball is dropped from a height of 3.0m above ahard concrete floor. After striking the floor the ball bounces upto a height of 2.0m above the floor. The ball was in contact withthe floor for 0.05s. A) Calculate the change in momentum (impulse) of the ballduring the interaction with the floor. B)Calculate the magnitude of the average force of the floor onthe ball during the interaction.Explanation / Answer
A 0.5 kg rubber ball is dropped from a height of 3.0m above ahard concrete floor. After striking the floor the ball bounces upto a height of 2.0m above the floor. The ball was in contact withthe floor for 0.05s. A) Calculate the change in momentum (impulse) of the ballduring the interaction with the floor.change in the momentum=m(-2*9.8*2-3*9.8*3)=-7.825kgm/sec B)Calculate the magnitude of the average force of the floor onthe ball during the interaction.
force= magnitude of change in momentum/time ofcontact=7.825/0.05=156.51N
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