you slide a 325N trunk up a 20 degree incline plane witha constant velocity by e

Question

you slide a 325N trunk up a 20 degree incline plane witha constant velocity by exerting a force of 211N parallel to theinclined plane. what is the component of the trunks weight parallel tothe plane? what is the size and direction of the friction force? what is the coefficient of friction? you slide a 325N trunk up a 20 degree incline plane witha constant velocity by exerting a force of 211N parallel to theinclined plane. what is the component of the trunks weight parallel tothe plane? what is the size and direction of the friction force? what is the coefficient of friction?

Explanation / Answer

weight W = 325 N angle = 20 degrees force F = 211 N the component of the trunks weight parallel to the plane = Wsin = 72.166 N the size and direction of the friction force f =Applied - component of weight in along inclined Since it moves with constant speed So, 211 N - 72.166 N = 138.83 N (c). we know f = mg cos the coefficient of friction = f / mg cos                                        = 0.4545   Since mg = W the size and direction of the friction force f =Applied - component of weight in along inclined Since it moves with constant speed So, 211 N - 72.166 N = 138.83 N (c). we know f = mg cos the coefficient of friction = f / mg cos                                        = 0.4545   Since mg = W

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