A student, m =63kg, falls freely from rest & strikes theground. During the colli
ID: 1764729 • Letter: A
Question
A student, m =63kg, falls freely from rest & strikes theground. During the collision with the ground, he comes to rest in atime of 0.04 sec. The average force exerted on him by the ground is+18,000N, where the upward direction is taken to be the positivedirection. From what height did the student fall? Assume that theonly force acting on him during the collision is that due to theground. Book answer: 6.7 m Thanks. A student, m =63kg, falls freely from rest & strikes theground. During the collision with the ground, he comes to rest in atime of 0.04 sec. The average force exerted on him by the ground is+18,000N, where the upward direction is taken to be the positivedirection. From what height did the student fall? Assume that theonly force acting on him during the collision is that due to theground. Book answer: 6.7 m Thanks.Explanation / Answer
A student, m =63kg, falls freely from rest & strikes theground. During the collision with the ground, he comes to rest in atime of 0.01 sec. The average force exerted on him by the ground is+18,000N, where the upward direction is taken to be the positivedirection. From what height did the student fall? Assume that theonly force acting on him during the collision is that due to theground. Book answer: 6.7 m Thanks.force exerted by the ground=change in the momentum/time ofcontact.
let he fall from a height h
so velocity he acquires by reaching the ground=2gh
so change in the momentum=(63*2*9.8*h-0)/0.01=18000N
as the student starts from rest his initial velocity=0m/sec
calculating we will get the answer.
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