In a physics lab, a cube slides down a frictionless incline asshown in the figur

Question

In a physics lab, a cube slides down a frictionless incline asshown in the figure , and elastically strikes another cube at thebottom that is only 1/9 its mass. If the incline is 30 cm high and the table is 90 cm off thefloor, where does each cube land? [Hint: Both leave theincline moving horizontally.] Im having alot of trouble w/ this question??? There is asimilar question in the Giancoli 6th Edition Physics book, Ch 7,problem #29. But even with a simliar example, my algebra isnot good enough to get the right answer. Can someone pleasehelp? Thanks. In a physics lab, a cube slides down a frictionless incline asshown in the figure , and elastically strikes another cube at thebottom that is only 1/9 its mass. If the incline is 30 cm high and the table is 90 cm off thefloor, where does each cube land? [Hint: Both leave theincline moving horizontally.] Im having alot of trouble w/ this question??? There is asimilar question in the Giancoli 6th Edition Physics book, Ch 7,problem #29. But even with a simliar example, my algebra isnot good enough to get the right answer. Can someone pleasehelp? Thanks.

Explanation / Answer

h = 30 cm, H = 90 cm momentum conservation: m(2gh) = mV + (m/9)*v (2gh) = V + v/9      (1) elastic collision: (2gh) = v - V       (2) v = 1.8(2gh) V = 0.8(2gh) t = (2H/g) the landing position of the smaller mass = vt = 3.6(hH) =1.87 m the landing position of the larger mass = Vt = 1.6(hH) =0.83 m

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