A. A helical pinion with 18 teeth is turning a gear with 41 teeth (P-12). The pi

Question

A. A helical pinion with 18 teeth is turning a gear with 41 teeth (P-12). The pinion is delivering 2 hp at 1200 rpm. If the helix angle is 15 degrees, the axial force on the shaft would be: (a) 37.513 Ilbs (b) 140.000 lbs (c) 61.463 lbs (d) 16.469 Ibs Is A but I don't know how to get the right answer B. A 20 degree pressure angle spur gear and pinion are running in mesh. The pinion has 150 in-lbs of torque turning at 300 rpm and a pitch diameter of 3.0 in. If the velocity ratio is 4.5, the force pushing the gears apart would be: (a) 31.251 lbs (b) 40.352 lbs (c) 36.397 lbs (d) 40.187 lbs Is C but I don't know how to get the right answer.

Explanation / Answer

PROBLEM-A:

Given data:

No. of teeth on the pinion, Z=18

Diametral Pitch, Pd=12 in.

Power delivered by the pinion, P= 2 HP

Speed, N=1200 rpm

Torque, T= (63000*Power)/ Speed

= (63000*2)/1200

= 105 lb-in.

Pitch circle diameter, d = Z/Pd

= 18/12 =1.5 in.

Axial Force on the shaft, F= (2*T)/d

= (2*105)/1.5

= 140 lbs.

PROBLEM-B:

Torque, T=150 in-lbs

pitch diameter, d= 3 in.

Transmitted Force, F= (2*T)/d

Separating Force, Fs= F* Tan(pressure angle)

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