Please see the figure. Need correct and clear answer. All the answers will be th

Question

Please see the figure. Need correct and clear answer. All the answers will be thankful :) Will rate quickly College physics review problem question - need help! Please see the figure. Need correct and clear answer. All the answers will be thankful :) Will rate quickly An electromagnetic plane wave is propagating in empty space. The magnetic field is given by B(x,y,z,t) = -JB 6 sin(kz + ohm t), where I is the unit vector in the + x direction, j is the unit vector in the + y direction, and k is the unit vector in the + z direction. Which of the following expressions describes the electric field of this electromagnetic wave? E(x,y,z,t) = iE0sin(kz + ohm t) E(x,y,z,t) = -iE0sin(kz + ohm t) E(x,y,z,t) = jE0sin(kz + ohm t) E(x,y,z,t) = -jE0sin(kz + ohm t) E(x,y,z,t) = kE0sin(kz + ohm t) E(x,y,z,t) = -kE0sin(kz + ohm t)

Explanation / Answer

E is perpendicular to B which is j

E is perpendilcular to wave direction which is k

so E must be along i

also E cross B should be along wave

-i cross -j = k (along the wave)

hence E = -iE0(kz+wt)

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