1. 01.25 points | Previous Answers SerPSE7 7 P.057.soln. My Notes Ask Your Te Th

Question

1. 01.25 points | Previous Answers SerPSE7 7 P.057.soln. My Notes Ask Your Te The ball launcher in a pinball machine has a spring that has a force constant of 1.20 N/cm. The surface on which the ball moves is inclined 10.0° with respect to the horizontal. If the spring is initially compressed 4.50 cm, find the launching speed of a 70 g ball after the plunger is released and fully extended. Friction and the mass of the plunger are negligible. 1.6 Your response differs from the correct answer by more than 10%. Double check your calculations. m/s Need Help? Talk to Tutor

Explanation / Answer

here,

spring constant , K = 1.2 N/cm = 120 N/m

theta = 10 degree

x = 0.045 m

mass of the ball ,m = 0.07 kg

let the final speed be v

using conservation of energy

initial potential energy of spring = final potential energy gained + final kinetic energy

0.5 * k * x^2 = m * g * x * sin(theta) + 0.5 * m * v^2

0.5 * 120 * 0.045^2 = 0.07 * 9.81 * 0.045 * sin(10) + 0.5 * 0.07 * v^2

solving for v

v = 1.82 m/s

the final speed is 1.82 m/s

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