10. (3 pts.) As part of his workout, a football layer runs up the steps in Aloha

Question

10. (3 pts.) As part of his workout, a football layer runs up the steps in Aloha Stadium, bringing his 95 kg body to a final height of 75 m above his starting point. a. How much mechanical work did he do to raise his body to that hei ght? h. T A. None B. 75J C. 735J D. 930 J E. 7,100J 070,000 J / pE b. If it took the athlete 55 seconds to get there, what was his power output? A. Zero B. 180 W C. 340 W 5,200 W F. 38,000 w P 4: Another 95 kg athlete runs 75 m along the flat track that encircles that playing field. How much mechanical work does he do against gravity? A. None B. 75 J C. 735 J D. 930 J 7,100J F)70,000 J

Explanation / Answer

a)

Mechanical Work Done

W=mgh =95*75*9.81=69896 J

W=70000 J

b)

Power output

P=W/t = 69896.25/55=1271 W

P=1300 Watts (approx)

c)

Work done on gravity on flat surface is zero .Therefore answer is none.

W=0

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