moodle-2017-2018.ca CAL STATE LA Question 5 Not yet answered Points out of 1.00

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moodle-2017-2018.ca CAL STATE LA Question 5 Not yet answered Points out of 1.00 Flag question An LA Dodger baseball player hits a 93 mph fastball out of the park for a home run. On making this hit, the ball left the bat at 110 mph after the initial impact. the ball left the bat at an angle of 45-degrees, with respect to the ground, calculate the maximum height of the ball, as it goes 'out of the park". Assume that the bat contacted the ball at 0.91 m above the ground. A Major-League Baseball has a mass of m = 0.145 kg. Select one: a. 32.7m b. 66.31 m C. 0.86.6 m d. 96.4 m Previous page Next page

Explanation / Answer

Maximum height in a projectile,

H = (u sin theta)^2/2g

Here u =110 mph = 0.447*110 m/s = 49.17 m/s

H = (49.17* sin 45 degree)^2/(2*9.8)

= 61.67 m

Maximum height above ground = 0.91+61.67

= 62.58m

Option b is closest

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