Please show all work. Will rate, good answer. Thanks! A linearly polarized elect
ID: 1770133 • Letter: P
Question
Please show all work. Will rate, good answer. Thanks!
A linearly polarized electromagnetic wave has an average intensity of 395 W/m2. This wave is directed towards two ideal polarizers (in real polarizers, transmission is also effected by reflection and absorption). Polarizer A is oriented with its transmission axis at an angle of 1 = 22.4° with the incident electric field. Polarizer B has its axis at an angle of 2 = 78.4° with the incident electric field, as shown in the figure.
What is the average intensity of the wave after it passes through polarizer A?
What is the average intensity of the wave after it passes through polarizer B?
Suppose that the two polarizers A and B are interchanged. What would the average intensity be after passing through both polarizers?
Explanation / Answer
here,
the initial intensity , I0 = 395 W/m^2
theta1 = 22.4 degree
theta2 = 78.4 degree
a)
the intensity of light passed through polarizer 1, I1= I0 * ( cos(theta1))^2
I1 = 395 * ( cos(22.4))^2 W/m^2
I1 = 337.6 W/m^2
b)
the intensity of light passed through polarizer 2, I2 = I1 * ( cos(theta2))^2
I2 = 337.6 * ( cos(78.4))^2 W/m^2
I2 = 13.70 W/m^2
c)
when the angles are interchanged
the intensity of light passed through polarizer 1, I1= I0 * ( cos(theta2))^2
I1 = 395 * ( cos(78.4))^2 W/m^2
I1 = 15.97 W/m^2
the intensity of light passed through polarizer 2, I2 = I1 * ( cos(theta1))^2
I2 = 15.97 * ( cos(22.4))^2 W/m^2
I2 = 13.70 W/m^2
the final intensity remains the same
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