please answer c 4 takes time t 0.53 R The Expert TA | Human sq45tx theexpertta.c

Question

please answer c

4 takes time t 0.53 R The Expert TA | Human sq45tx theexpertta.com/Common Take | Help HNVS Begin Date: 10302017 1210140 AM Due Date: M End Date :00 PM (8%) Problem 6: The Moon orbits around the Earth and also spins on its axis 33% Part (a) What is the angular momentum ofthe Moon in its ortnt around Earth? 33% Part (b) What is the angular momentum of the Moon in its rotation around its axs? 33% Part (c) How many times larger is the oth ital at gularmementum than I er et nal annlar m mentum or the M ori, Grade Sums Larh Late Work cos) 1814, | HOME SI cotan cos acotansinh colanh aSIn cosh Attempts res . Degrees Radians dylailed vi Suhmit I give up Hints: 'I for u-deduction. Hints nmamalg Feedback: 0%, deduction per festack. -I the oebstal angular momentum is lrger, make sre the numher your enter bere is greater than one

Explanation / Answer

The Moon’s angular momentum with respect to the Earth comes from two sources: first, its orbit around the Earth; and second, from its spin around its own axis.

Let us first suppose that:

The moon’s angular velocity (both for its orbit and its rotation, since its tidally locked in a 1:1 orbit) is:

= 2 / T = 2 / 2.3606e6 s = 2.66169e-6 rad/s

The Moon’s rotational moment of inertia is:

I = 2/5 M a^2 = 0.4(7.3459e22 kg)(1.7375e6 m)^2

Or

I = 8.87063e34 kg m^2

So the rotational angular momentum Lis:

L = I = (8.87063e34 kg m^2)(2.66169e-6 rad/s)

Or

L = 2.361087e29 kg m^2/s

Now compare that to the Moon’s orbitalmoment of inertia:

I = Mr^2 = (7.3459e22 kg)(3.85e8 m)^2

Or

I = 1.0888e40 kg m^2

And its correspondingly larger orbital angular momentum:

L = I = (1.0888e40 kg m^2)(2.66169e-6 rad/s)

Or

L = 2.89805e34 kg m^2/s, about 122,741 times larger!

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.