that you did in class. They there is a link to your lab manual at the bottom of

Question

that you did in class. They there is a link to your lab manual at the bottom of this question, if you need to refer back to the lab background and Angular Position and Velocity Setup Place a 10 mass on ne mass hanger weghthe harge and mass, and mod fs wake in 2 With string wound up so that the mass hanger hangs just below the puiley not overwind to rescale the graph it needed. This data will be labeled as "Ru and eoond the on Table , Table 1 6 Repeat the 7. Detach motion accessory and weigh it, and measure ts radius. Recond these values in Table 2 Table 2

Explanation / Answer

given 10 g mass

mass and weights measurements

#1 16g

#2 27 g

mass of disc M = 120 g

radius r = 4.6 cm

radisu of step pulley, R = 1.4 cm

also, w = mt

#1, m = 14.6

#2, m = 24.5

1. moment of inertia of the disc = 0.5*m*r^2 = 0.5*0.120*(4.6*10^-2)^2

Id = 0.00012696 kg m^2

2. now, from the slope of the graph, m is angular acceleration

now, torque = T

T = I*m

for #1, T = 0.001853616 Nm

for #2, T = 0.00311052 Nm

3. force generated by hangar = T/R

so for #1, F = T1/R = 0.13240114285714285714285714285714 N

for #2, F = T2/R = 0.22218 N

4. mass = F/g

for #1, m = 13.4965 g

for #2, m = 22.648 g

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