Write your answers (with appropriate precision) in the blanks provided. Indicate

Question

Write your answers (with appropriate precision) in the blanks provided. Indicate all units. 2. The following experiment is conducted with a triple pulley. Use the information to fill in the table. 300 Mass attached to the pulley (g) Height by which the mass is raised (cm) Work done by the force of gravity Reading of the upper "suspension" scale (N) Expected theoretical reading of the upper 30.0 3.90 suspension" scale (N) % error of the reading of the upper scale Reading of the bottom "applied force" scale (N) Expected theoretical reading of the "applied 0.700 force" scale (N) % error of the reading of the "applied force" scale Measured distance by which the "applied force" 1.0 was pulled (m) Work done by the "applied force" % error of the work done by the "applied force"

Explanation / Answer

1. The work done by the force of gravity = Force x distance.

Here, Force = mg = 0.3 kg x 9.8 m/sec2 = 2.94 N

Work done = mgh = 2.94 N x 0.3 m = 0.882 Joule

2. The expected theoretical reading of the upper suspension scale = 2.94 N

3. % error = [(theoretical value – experimental value)/theoretical value] x 100

               = [(2.94 -3.90) / 2.94] x 100

               = -32.65%

4. The expected theoretical reading of the applied force (bottom) = -2.94 N (As F(gravity) = -F(tension)

5. % error = [(2.94 -0.700)/2.94] x 100

                = 76.19%

6. Work done by the applied force = -2.94 x 1 = -2.94 Joule

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