PROBLEM 2 -8 points Three identical balls are placed so that there is one ball i

Question

PROBLEM 2 -8 points Three identical balls are placed so that there is one ball in each of three different beakers of liquid. As shown in the picture, the ball in liquid A floats with 80% of its volume submerged; the ball in liquid B floats with 40% of its volume submerged, and the ball in liquid C sinks to the bottom. A:80% B:40% : 100% [1 point] (a) Rank the liquids based on their density, from largest to smallest [1 point] (b) Rank the situations based on the buoyant force applied by the liquid on the ball. We are now given the information that the density of liquid A is 1200 kg/m*. 2 points] (c) Calculate the density of one of the balls. The balls are identical, remember. 2 points] (d) Calculate the density of liquid B. 2 points] (e) We are also given that the buoyant force applied to the ball in situation C is exactly half that applied to the ball in situation B. Calculate the density of liquid C

Explanation / Answer

a)The liquid with highest density will exert maximum force thus not allowing the ball to immerse into it

thus B>A>C.

b)From the same argument

B>A>C

c)Since at equilbrium the weight of ball is equal to buypnt force

0.8* V*Density of liquid = weight of ball

thus density of ball =0.8*density of liquid

=0.8*1200=960km/m3

d)Using the same argument we get

density of B=960/0.4=2400 kg/m3

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