Analysis Refer to the table below for the Accepted values of the conductivity of

Question

Analysis Refer to the table below for the Accepted values of the conductivity of the samples. Thermal Conductivity-Accepted Values Material Glass Lexan (plastic) Pine Wood Sheet Rock (plaster) k(cal / cm°Cs) 20.6 x 104 4.6 x 104 1) Calculate the percent difference between the measured and accepted values of k for the four samples. Show a sample calculation. Pine 4 -4 difference-measured-accepted x 100%-3.9H0K(W/Wcs)-4.on accepted k measured (cal / cm s) k accepted (cal / cm s) % difference Sample Material #1 | Pine | 9.910 4.0 0 3.375 122.5 X104 |20.61041 9./69 #2 san 2) Briefly comment on the accuracy ofyour experiment (Material #1) and summarize the any discrepancies between your measured value and the accepted one. 166

Explanation / Answer

4. The accuracy of measurement is greatest for glass and wood while it is least for Plaster and Plastic. Yes there exists a pattern. As in case of plastic and plaster, accuracy is poor.

5. Thermal conductivity of aluminium is very high and hence it can easily be eliminated from the measurements as all the other materials used have quite low thermal conductivity.

6. According to the measurements, pine is the best insulator as it has lowest thermal conductivity.

7. R(sheet rock) = 2985.07 cal/oCs

R (pine wood) = 6666.67 cal/oCs

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