Determine the work of the force F = 410 Nshown in (Figure 1) when it displaces 2
ID: 1771018 • Letter: D
Question
Determine the work of the force F = 410 Nshown in (Figure 1) when it displaces 2 m.
Express your answer to three significant figures and include the appropriate units.
U = ________
Determine the work of the force shown in (Figure 2) when it displaces 2 m.
Express your answer to three significant figures and include the appropriate units.
U = ________
Determine the work of the force F=(5s2) Nshown in (Figure 3) when it displaces 2 m.
Express your answer to three significant figures and include the appropriate units.
U = ________
Determine the work of the force F = 120 Nshown in (Figure 4) when it displaces 2 m.
Express your answer to three significant figures and include the appropriate units.
U = ________
Determine the work of the force shown in (Figure 5) when it displaces 2 m.
Express your answer to three significant figures and include the appropriate units.
U = ________
Spring shown in (Figure 6) is originally compressed 3 m . Determine the work of the force exerted by spring when it displaces 2 m.Suppose that k = 16 N/m .
Express your answer to three significant figures and include the appropriate units.
U = ________
Determine the work of the force F = 200 Nshown in (Figure 7) when it displaces 2 m.
Express your answer to three significant figures and include the appropriate units.
U = ________
(Yes this is actually one single problem on MasteringEngineering......)
2 m 4Explanation / Answer
Work done = F.d = F d cos(theta)
W = (410) ( 2) (3 /5) = 492 J ..........Ans
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W = 410 x 2 x cos90 = 0
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W = integral of F ds =
dW = 5 s^2 ds
W = (5 / 3) s^3 from 0 to s
W = (5/3) (2^3 - 0^3) = 13.33 J
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W = 120 x 2 x 3/5 = 144 J
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W = area under the curve x 4 / 5
W = ((20 x 1 / 2) + (20 x 1)) x 4/5
W = 24 J
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W = k (xf^2 - xi^2) / 2
W = 16 (2^2 - 3^2) / 2 = - 40 J
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w = 200 X 2 X -4/5 = -320 J
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