ligular momentum state of 4: A) 6 B) 10 C) 14 D/18 35. Use your answers from the

Question

ligular momentum state of 4: A) 6 B) 10 C) 14 D/18 35. Use your answers from the previous questions to determine the total number of possible quantum states for this electron: A) 17 B) 36 0 D) 37 Find the binding energy and the binding energy per nucleon of the 0 nucleus. Hint: Use Table Chapter 30 30-1 36. Binding energy of the hydrogen components A) 931.50 MeV B) 11265.47 Mev c) 5632.73 Mev D) 16898.20 MeV 7. Binding energy per nucleon of the hydrogen components: A) 51.75 MeV B) 469.39 MeV C) 1877.58 Mev D) 1408.18 MeV 8. Binding energy of the neutron components:

Explanation / Answer

Chapter 30

Mass defect, Dm = (6 x 1.008664 u) + (6 x 1.007276 u) - 12.000 u = 0.0990 u

The binding energy in the carbon-12 atom is therefore 0.0990 u x 931.5 MeV/u = 92.21 MeV

Binding energy per nucleon for 6C12 = 92.15/12 = 7.68 MeV/nucleon

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