Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

The electrical force between two charged objects depends on the number of electr

ID: 1771076 • Letter: T

Question

The electrical force between two charged objects depends on

the number of electrons in the objects.

the total number of protons in both objects.

the sum of the net charges on the objects.

the product of the net charge on each of the two objects.

just the magnitude of the largest charge

If the Potential Energy of an Electric Charge increases, then the Electric Potential decreases.

True

False

We move a 6 C Electric Charge from a point where the Electric Potential is 30 V to a point where the Electric Potential is 40 V. The amount of Work done in this process is:

60 J

20 J

40 J

50 J

Two Resistors of 10 Ohms each are connected in Parallel in a certain Electric Circuit. The resultant Electric Resistance is 5 Ohms.

True

False

In a metallic wire the Electric Current is due to the motion of the free protons in the metal.

True

False

An Electric Current of 15 A is crossing a 10 Ohms Resistor. The Voltage difference at the ends of the Resistor must be 50 V.

True

False

An Electric Current of 2 A is crossing a 5 Ohms Resistor. The Voltage difference at the ends of the Resistor must be 10 V.

True

False

When we say that an Electric Device involves an Electric Power of 60 Watt, we mean that each second 60 Joules of Electric Energy is consumed.

True

False

the number of electrons in the objects.

the total number of protons in both objects.

the sum of the net charges on the objects.

the product of the net charge on each of the two objects.

just the magnitude of the largest charge

Explanation / Answer

The electric force depends on product of charge between two objects and distance between two objects. Therefore option 4 is correct

Please post other questions separately

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote