A 1,380-N crate is being pushed across a level floor at a constant speed by a fo
ID: 1771194 • Letter: A
Question
A 1,380-N crate is being pushed across a level floor at a constant speed by a force f of 250 N at an angle of 20.0° below the horizontal, as shown in the figure a below. 20.0 1200 (a) What is the coefficient of kinetic friction between the crate and the floor? (Enter your answer to at least three decimal places.) 168 (b) If the 250-N force is instead pulling the block at an angle of 20.0° above the horizontal, as shown in the figure b, what will be the acceleration of the crate? Assume that the coefficient of friction is the same as that found in part (a) 0.129x Your response differs from the correct answer by more than 10%. Double check your calculations. m/s2Explanation / Answer
here,
b)
force , F = 250 N
theta = 20 degree
coefficient of kinetic friction , uk = 0.168
the accelration , a = net force /effective mass
a = ( F * cos(theta) - uk * ( weight of crate - F * sin(theta))) /(mass of crate)
a = ( 250 * cos(20) - 0.168 * (1380 - 250 * sin(20))) /( 1380/9.81) m/s^2
a = 0.124 m/s^2
the accelration of the crate is 0.124 m/s^2
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