2345 67 89 10 11 12 13 14 15 Total Points gnment Submission e this assignment, y

Question

2345 67 89 10 11 12 13 14 15 Total Points gnment Submission e this assignment, you submit answers by question parts ignment Scoring ur last submission is used for your score The number of sulrnssons "enmanngts eachmtion pat only changes , you-tet o chage the man A motonst drives south at 30.0 m/s for 3.00 mrthen turns west and travels at 25.0 m/s for 2 60 me, and hily travels northwest at 30.0m/s br 1.00 mr. For th.60 try,d the therg- (a) total vector displacement Your response differs significantly from the correct anewer, Rework your solution from the beginning and check each step carefly m(magntude) 3 Your response differs from the correct answer by more than 10%. Duuble check your calculations south of west (b) average speed nVs (c) average velocity south of west Your response dimer" nom the correct answer by more than 10% Douaiecheck you, calculaton.-.(man Practice Another Verson Submt Answer Save Progress

Explanation / Answer

just break each step into its vector components, then add all the x components, and y components, separately.

lets say, east as +x and north as +y

1) x=0, y=-(30 x 180) = -5400m
2) x=-(25 x 60 x 2.6) = -3900m, y=0
3) x=-(30 x 60 x cos45) = -1800cos(45)=-1273m, y=1800*sin(45)=1273m

final displacement = (1) + (2) + (3) =

D, (x = 0 - 3900 -1273 = -5173 m, y = -5400 + 0 + 1273 = -4127 m)

magnitude of D = sqrt((5173)2 + (4127)2) = 6617.5 m

direction = tan-1(4127/5173) = 38.58o south of west

b) avg speed = (5400 + 3900 + 1800)/(6.6 x 60) = 28.03 m/s

c) avg velocity = displacement/ time = 6617.5/(6.6 x 60) = 16.71 m/s , 38.58 south of east

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