Problem 21.48 Part A A-60 nC charged particle is in a uniform electric How much

Question

Problem 21.48 Part A A-60 nC charged particle is in a uniform electric How much work is done on it by the external force? Express your answer to two significant figures and include the appropriate units field E (20 V/m, east). An external force moves the particle 4.0 m north, then 5.0 m east, then 6.0 m south, and finally 4.0 m west. The particle begins and ends its motion with zero velocity. Submit My Answers Give Up Correct Part B What is the potential difference between the particle's final and initial positions? Express your answer to two significant figures and include the appropriate units = 1 Value Units Submit My Answers Give Up

Explanation / Answer

When the charged particle moves perpendicular to the field, no work is done. So we need only consider movement in an E-W directions. The overall displacement parallel to the field vector is 1m East.

The work is therefore = E *d* q = -60*10^-9 *1*20 = -1.2 * 10^-6 J = -1.2 uJ

The potential difference between the starting and final positions is

V= W/q = 20 V.

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