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The Expert TA Human- x Chegg Study | Guided sex C Secure | https://use11fl.theexpertta.com/Common/TakeTutorialAssignment.aspx : Apps Bookmarks T ONE.UF my.ufl.edu-Univers -UF Email C user Dashboard physics Homework Class Management | Help HW 7 Begin Date: 9/25/2017 11:00:00 AM - -Due Date: 10/9 2017 11:00:00 AM End Date: 109/2017 11:00:00 AM (10%) Problem 3: A ball with an initial velocity of 9.5 m/s and mass 2.9 kg moves at an angle 59.5° above the horizontal. The ball hits a vertical wall and bounces off so that it is moving 59.5 above the horizontal, moving in the opposite direction with the same speed. See the figure. Assignment Status Click here for detailed view what was the magnitude of the impulse delivered by the wall, in kilogram meters per second? Problem Status Grade Summary Completed Completed 59% 959% sin0 cotan asinacos0 atan0 acotan0sinh0 cosh0 tanhcotanh Partial cos0 Attempts remaining: 4 (5% per attempt) detailed view Completed Completed 6 Completed Completed Completed Completed 10 Completed 596 Degrees Radians Hint Feedbachk I give up Hints: 100 deduction per hint. Hints r Feedback: 1% deduction per feedback Submission History Hints Feedbaclk Totals O Type here to search ^41) 10/4/2017 5:38 PM

Explanation / Answer

initial velocity vi = 9.5*cos59.5 i + 9.5*sin59.5 j

after bouncing off vf = -9.5*cos59.5 i + 9.5*sin59.5 j

initial momentum Pi = m*vi

final momentum Pf = m*vf

Impulse = change in momentum

Impulse = Pf - Pi

Impulse = 2.9*(-9.5*cos59.5 i + 9.5*sin59.5 j - 9.5*cos59.5 i - 9.5*sin59.5 j)

Impulse = -2.9*2*9.5*sin59.5 i = -47.5 i

magnitude = 47.5 kg m/s <<<-----------ANSWER

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