to better understand the concept of static equilibrium a 10/19/2017 11:55 PM 13.
ID: 1772442 • Letter: T
Question
to better understand the concept of static equilibrium a 10/19/2017 11:55 PM 13.3/100 Print Calculator Periodic Table tuestion 3 of 15 Sapling Learning To better understand the concept of static equilibrium a laboratory procedure asks the student to make a calculation before performing the experiment. The apparatus consists of a round level table in the center of which is a massless ring. There are three strings tied to different spots on the ring. Each string passes parallel over the table and is individually strung over a frictioniess pulley (there are three pulleys) where a mass is hung. The table is degree marked to indicate the position or angle of each string. There is a mass m, = 153 g located at 245° and a second mass m-215 g located at 287". Calculate the mass my and location (in degrees), ,which will balance the system and the ring will remain stationary Number NumberExplanation / Answer
Solution-
From the question we have-
m1 = 0.153kg. weight = (.153 x 9.8) = 1.499N
m2 = 0.215kg. weight = 2.107 N
Now let us rotate the table 24.5 degrees anticlockwise,
Hence m1 is at 0. That puts m2 at (287 - 24.5) = 262.5 degrees
(262.5 - 180) = 82.5 degrees west of south
South component of m2 = (cos 82.5) * 2.107 = 0.275N
West component = (sin 82.5 ) * 2.06 = 2.042N
Now let us subtract South component from weight m1, = 1.499 - 0.275 = 1.224 N acting North
Weight of M3 = sqrt. (2.042^2 + 1.224^2), = 2.38N divided by g = mass of 0.243kg or 243g
Direction = arctan (1.224 / 2.042) = 30.94 degrees South of East
Now "rotate" the table back the 24.2 degrees clockwise, (24.2 + 30.94 + 90) = 145.14 degrees, is where to place the m3 of 253g. (Here the "90" is due to east is 90 deg. from North, and the 30.94 was from East)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.