#16 Defining Mechanical Equilibrium A necessary condition for mechanical equilib
ID: 1772448 • Letter: #
Question
#16 Defining Mechanical Equilibrium A necessary condition for mechanical equilibrium is O A. net or total forces on all system components are zero. B. net or total forces on at least one system component are zero. O C. net or total horizontal forces on all system components are zero 0 D. net or total vertical forces on all system components are zero. #17 Centripetal Force and Circular Motion moves at a constant speed of 4.58 m/s in a circle with a 2.54 meter radius. What is the magnitude of the centripetal force responsible for the circular motion? A, 22.7 N B. 28.5 N C. 36.3 N o D. 42.8 N #18 Centripetal Force and Circular Motion A 1.88 kg mass follows a circular trajectory, moving with a constant velocity. If the centrally directed force on the mass is 23.5 Newtons, what is the magnitude of the acceleration of the nass? A. 5.60m/82 0 B. 7.25 m/82 ° C. 9.80 m/s2 O D. 12.5 m/s #19 Centripetal Force and Circular Motion In #18, what is the direction of the acceleration? 0 A. The acceleration is always directed inward. B. The acceleration is directed inward only if the motion is in the counter low ise sense. ° C. The acceleration is always directed outward. 0 D. The acceleration is tangentially directed. #20 Centripetal Force and Circular Motion A small object with a mass of 1.50 kg is attached to a string of negligible mass follows a horizontal circular trajectory with a radius of 3.25 meters and completes a circular orbit once per 11.5 seconds, What is the tension in the string? 0 A. 0.852 N 0 B. 1.17 N ° C. 1.46 N D. 1.61 NExplanation / Answer
16)
for any system to be in equillibrium the total horizontal and vertical forces should be equal to zero so total force is zero
Answer is A. net or total forces on all system components are zero
17)
Given m = 3.45 kg
v = 4.58 m/s
r = 2.54 m
centripetal force F = m * v^2 / r
F = (3.45 * 4.58^2) / 2.54
F = 28.49 N
Answer is B. 28.5 N
18)
m = 1.88 kg F = 23.5 N
acceleration a = F / m = 23.5 / 1.88
a = 12.5 m/s^2
Answer is D. 12.5 m/s^2
19)
the acceleration is always directed along the radius
Answer is A. The acceleration is always directed inward.
20)
m = 1.5 kg
r = 3.25 m
t = 11.5 s
speed v = distance / time
v = 2pi*r / t
v = 2pi * 3.25 / 11.5
v = 1.77 m/s
tension is the centripetal force so
T = m * v^2 / r
T = (1.5 * 1.77^2) / 3.25
T = 1.46 N
Answer is C. 1.46 N
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