Sam and Zelda both horizontal forces box of mass 12kg. Sam exerts a 40 N force d

Question

Sam and Zelda both horizontal forces box of mass 12kg. Sam exerts a 40 N force due south and Zelda exerts a 30 N force in a direction 23 degree south of east. both forces remain constant as the box is accelerated from rest across a horizontal floor. friction is negligible. determine the displacement of the box (magnitude and direction) during the first 3.0s of its motion. Sam and Zelda both horizontal forces box of mass 12kg. Sam exerts a 40 N force due south and Zelda exerts a 30 N force in a direction 23 degree south of east. both forces remain constant as the box is accelerated from rest across a horizontal floor. friction is negligible. determine the displacement of the box (magnitude and direction) during the first 3.0s of its motion. Sam and Zelda both horizontal forces box of mass 12kg. Sam exerts a 40 N force due south and Zelda exerts a 30 N force in a direction 23 degree south of east. both forces remain constant as the box is accelerated from rest across a horizontal floor. friction is negligible. determine the displacement of the box (magnitude and direction) during the first 3.0s of its motion.

Explanation / Answer

After making the free body diagram of the body

We will analyze the net force in both x and y directions so that we can find net accelerations in each directions.

So in x direction

Fnet= 30cos23

= 27.615 N i

Also F=ma

So ax=2.301 i

In vertical direction

Fnet= 30sin23-40

=-28.278N j

Again F=ma

ay= - 2.356 j

Now applying second equation of motion

As initial velocity is zero

So,

X= 0.5*2.301*9

10.35 similarly

Y=0.5*(-2.356)*9

=-10. 6

So displacement of the body is

10.35i - 10.6j

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