A charge q 1 = +2.72 µC is at a distance d = 1.03 m from a second charge q 2 = 5

Question

A charge

q1 = +2.72 µC

is at a distance

d = 1.03 m

from a second charge

q2 = 5.77 µC.

(a) Find the electric potential at a point A between the two charges that is

d/3

from q1. Note that the location A in the diagram above is not to scale.

What is the potential due to a point charge at a particular distance from it? Did you consider the sign of each charge when calculating the electric potential? V

(b) Find a point between the two charges on the horizontal line where the electric potential is zero. (Enter your answer as measured from q1.)

If the total potential at a location has to be zero, what conclusion can you draw about the individual potentials at that location due to

q1 and q2?

Explanation / Answer

a) Potential is given by V = summation kq/r

= 9e9*(2.72e-6/(1.03/3) + - 5.77e-6/(1.03*2/3))

= - 4325 V

Potential due to charge q at distance r is kq/r, where we have to consider sign also.

B) The individual potential due to one charge will be negative of other.

k*(q1/x + q2/(d-x)) =0

2.72/x - 5.77/(1.03-x) = 0

x = 0.33 m answer

The individual potential due to one charge should be negative of that due to other charge.

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