A 0.072-kg ball is thrown at 30 m/s toward a brick wall. (a) Determine the impul

Question

A 0.072-kg ball is thrown at 30 m/s toward a brick wall. (a) Determine the impulse that the wall imparts to the ball when it hits and rebounds at 30 m/s in the opposite direction. (The initial direction of the ball is defined as the positive x direction.) (b) Determine the impulse that the wall imparts to the ball when it hits and rebounds at an angle of 54° in the horizontal and vertical components in kg*m/s. (c) If the ball thrown in part (b) contacts the wall for 0.02 s, determine the magnitude and direction of the force that the wall exerts on the ball in the horizontal and vertical components in N.

Explanation / Answer

Here ,

a) impulse imparted = change in momentum

impulse imparted = 0.072 *(v - (-u))

impulse imparted = 0.072 * (30 - (-30))

impulse imparted = 4.32 Kg.m/s

b) if the angle is 54 degree with the horizontal

impulse imparted = 0.072 *(v - (-u)) * cos(theta)

impulse imparted = 0.072 * (30 - (-30)) * cos(54 degree)

impulse imparted = 2.54 Kg.m/s

c)

force acting on the wall = 2.54/.02 = 127 N

the force acting on the wall is 127 N

vertical component is zero

horizontal component of force = 127 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.