tw afari File Edit View History Window Help webassign.net 5P071 Two masses are c
ID: 1773123 • Letter: T
Question
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Explanation / Answer
This is called an Atwood machine
T-m1g=m1a
m2g-T=m2a
Eliminating T and solving for the acceleration we get
a=(5.3-2.55)/(5.3+2.55)*9.8=3.43 m/s^2
s=1/2at^2
v=at
so v=sqrt(2as). In this case s=2, the halfway point
A)
so v=3.7 m/s
B) when the 5.3 weight hits the floor the velocity is
sqrt(2*4*3.43)=5.23 m/s
C) v = u - gt
v = 0
t = u/g = 5.23/9.8 = 0.533 s
t is the time during which block m1 travels further upward
S = ut - 1/2gt^2 = 5.23*0.533 - 0.5*9.8*0.533^2
S = 0.175 m
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