Need Help? mentsd graph nment5d Linear linal Starting from rest, a 52-kg block s

Question

Need Help? mentsd graph nment5d Linear linal Starting from rest, a 52-kg block slides Hk 0.436. 2.20 m down a rough 30.0° Indine. The coefficient of kinetic friction between the block and the Incline Is one din (a) Determine the work done by the force of gravity. 51 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. jepr health (b) Determine the work done by the friction force between block and incline. -39 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake m your calculation. Lab Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. 3 (c) Determine the work done by the normal force RSt (d) Qualitatively, how would the answers change if a shorter ramp at steeper angle were used to span the same vertical height? steeper angle would make sin theta bigger so work gravity would get bigger w friction would be less since it would slide on less ramp

Explanation / Answer

a] Work Done by force of gravity = W = [mgsin30]S

=> W = [5.2 x 9.8sin30]2.2 = 56.056 J

b] Work Done by frictional force =

Wf = - ukRS = - [ukmgcos30]S

=> Wf = - 0.436 x (5.2 x 9.8cos30) x 2.2 = - 42.332 J.

d] Work Done by gravity will be the same even for a smaller angle since the sine decreases but to span the same height, the length of the slope increases thereby nullifying each others effects.

Work Done by friction will increase since cos term will increase in value and the length of the slope will also increase to keep the same height as before.

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