JU My Print Center WileyPLUS-Home /.. e to S Cutnell, Physics, 10e GENERAL PHYSI

Question

JU My Print Center WileyPLUS-Home /.. e to S Cutnell, Physics, 10e GENERAL PHYSICS (PHYS 2001/2002) ctice Assignment Gradebook ORIONDownloadable eTextbook ment The drawing shows a skateboarder moving at 5.70 m/s along a horizontal section of a track that is slanted upward by -460" above the h izontal at its end, which is the ground. When she leaves the track, she follows the characteristic path of projectile motion. Ignoring friction and air resistance, find the maximum height H to which she rises above the end of the track. Units the tolerance is +/-2% GO TUTORIAL LINK

Explanation / Answer

Intial velocity, v = 5.70 m/s

Vertical component of the velocity, vy = v*sin theta = 5.70*sin46 = 4.10 m/s.

So, maximum height attained by the skater from this point, h = vy^2 / (2*g) = 4.10^2 / (2*9.81) = 0.86 m.

Therefore, maximum height of the skater from the initial point -

H = h + 0.57 = 0.86 + 0.57 = 1.43 m

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