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Chrome File Edit View History Bookmarks People Window Help 4) 55% [ Mon 2:15 PM

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Question

Chrome File Edit View History Bookmarks People Window Help 4) 55% [ Mon 2:15 PM a //LI WileyPLUS d Secure https://edugen.wileyplus.com/edugen/student/mainfr.uni !) Jenna Apps Chromecast WileyPLUS Cutnell,Phyaics,10 General Physics 1 (Fall 2017) (APHY105) Home Read, Study & Practice Gradebook ORION Downloadable cTextbook Assignment> Open Assignment FULL SCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Homework 5 (Chapters 1-3) Chapter 02, Problem 79 Consult Concept Simulation 2.1 for help in preparing for this problem. A cheetah is hunting. Its prey runs for 3.70 s at a constant velocity of +7.50 m/s. Starting from rest, what constant acceleration must the cheetah maintain in order to run the same distance as its prey runs in the same time? hapter 02, Problem Number Units GO the tolerance is +/-2% Click if you would like to Show Work for this question: SHOW HINT Review Results by St LINK TO TEXT LINK TO TEXT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor Question Attempts: 0 of 4 used SAVE FOR LATER SUBMIT ANSWER Earn Maximum Points available only if you answer this question correctly in three attempts or less.

Explanation / Answer

From the given question

time of prey(t)=3.70 s

speed of prey(v)=7.5 m/s

distance travelled by prey(s)= 3.7 * 7.5=27.75 m

initial velocity of chetaah(u)=0 m/s

distance covered by chetah(s)= 27.75 m

time taken by chetaah(t)=3.7 s

s= ut + (1/2)at2

27.75=0 + (1/2)a(3.72)

a=(27.75)*(2)/(3.72)

a=4.05 m/s2

Hence acceleration of chetaah is 4.05 m/s2

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