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Two point charges (q1 3.4C and q 8.9 C) are fixed along the x-axis, separated by

ID: 1773723 • Letter: T

Question

Two point charges (q1 3.4C and q 8.9 C) are fixed along the x-axis, separated by a distance d = 7.5 cm. Point P is located at (x,y)- (d,d) Th 91 Ti 1) What is Ex(P), the value of the x component of the electric field produced by q1 and q2 at point P? N/C Submit Ti You currently have 0 submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. Ti 2) What is Ey(P), the value of the y-component of the electric field produced by q1 and gz at point P? Ti N/C Submit You currently have 0 submissions for this question. Only 10 submission are allowed You can make 10 more submissions for this question. Ti 3) 43 A third point charge q3 -3.6 uC is now positioned along the y-axis at a distance d-7.5 cm from q1 as shown. What is Ex(P), the x-component of the field produced by all 3 charges at point P? N/C Submit You currently have 0 submissions for this question. Only 10 submission are allowed You can make 10 more submissions for this question 4) Suppose all charges are now doubled (ie., q1- -6.8 HC, q2-17.8 uC, q3 7.2 HC), how will the electric field at P change? Its magnitude will increase by less than a factor of two and its direction will remain the same Its magnitude will increase by less than a factor of two and its direction will change Its magnitude will double and its direction will remain the same Its magnitude will double and its direction will change Submit You currently have 0 submissions for this question. Only 10 submission are allowed

Explanation / Answer


(1)


E1x = -k*Q1*cos45/r1^2

r1 = sqrt(d^2+d^2) = d*sqrt2


E1x = -9*10^9*3.4*10^-6*0.075*cos45/(2*0.075^2)

E1x = -144250 N/C


for charge Q2 , electric field at point p is along y axis there is no x component

E2x = 0

Ex(p) = -144250 N/C

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(2)

E1y = -k*Q1*sin/r1^2

r1 = sqrt(d^2+d^2) = d*sqrt2


E1y = -9*10^9*3.4*10^-6*0.075*cos45/(2*0.075^2)

E1y = -144250 N/C

for charge Q2 , electric field at poinp is along y axis


E2y = k*Q2/d^2 = -9*10^9*8.9*10^-6/(0.075^2) = 14240000

Ex(p) = 14240000-144250 N/C = 14095750 N/C

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3)

E3x = k*Q3/d^2 = 9*10^9*3.6*10^-6/0.075^2 = 5760000 N/C

Ex(p) = 5760000 -144250 = 5615750 N/C

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4)

E = sqrt(Ex^2 +Ey^2)

if chares are doubled Ex and Ey also double


E' = 2*E


Its magnitude will double and the direction will remain same

=================

Increase the magnitude and keep its sign the same

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