Exercise 24.6 - edited by Dr. McCormick Part A A parallel-plate capacitor with c
ID: 1773782 • Letter: E
Question
Exercise 24.6 - edited by Dr. McCormick Part A A parallel-plate capacitor with capacitance C and circular plates is connected to a battery with voltage V. After the capacitor is fully charged, the battery is disconnected without loss of any of the charge on the plates. A voltmeter is connected across the two plates without discharging them. What does it read? Submit My Answers Give Up Part B What would the voltmeter read if the plate separation were doubled? Submit My Answers Give Up Give Up Part C What would the voltmeter read if the radius of each plate were doubled, but their separation was unchanged?Explanation / Answer
Potential different across capacitor = V
Charge stored on capacitor = Q = CV
If we remove the battery then charge on the capacitor will remain constant but here V = Q/C
In first case C is also constant so reading by voltmeter will V.
(b) as C = epsilon×Area/ distance between plate
New capacitance C' = C/2 ( as distance between plate is doubled )
Q' = Q
C'V' = CV
C/2 *V' = CV
V' = 2V
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