(17%) Problem 2: A golf ball is dropped from a height ofhi 3.45 m above the grou
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Question
(17%) Problem 2: A golf ball is dropped from a height ofhi 3.45 m above the ground. After it bounces, it only reaches a height 2.07m above the ground. The golf ball has mass m-0.1905 kg. Randomized Variables h1 3.45 nm i2 2.07m m-0.1905 kg magni ogram Grade Summary Deductions 0% Potential 100% 7 8 9 4 56 1 23 0 sin0 coso asino tan() | |( acoso Submissions cotan detailed view cosh( ) | tanh() cotanh0 0 END Degrees Radians I give up Hint Hints: 2% deduction per hint Hints remaining - 33% Part (b) newtons? If the golf ball was in contact with the ground for,-0.18 s, what was the magnitude of the constant force Facting on it, in 33% Part (c) How much energy in Joules, did the golf ball transfer to the environment during the bounce? AllExplanation / Answer
given,
mass of ball = 0.1905 kg
h1 = 3.45 m
h2 = 2.07 m
by conservation of energy
initial energy = final energy
initial energy = mh1g
final energy = 0.5 * mv1^2
mh1g = 0.5 * mv1^2
h1g = 0.5 * v1^2
3.45 * 9.8 = 0.5 * v1^2
v1 = 8.223 m/s
for height h2
2.07 * 9.8 = 0.5 * v2^2
v2 = 6.369 m/s
impulse = change in momentum
impulse = m * v2 - m * v1
impulse = m * (v2 - v1)
impulse = 0.1905 * (6.369 - (-8.223))
impulse = 2.779 kg . m/s
impulse = force * time
2.779 = force * 0.187
force = 14.861 N
energy lost = change in kinetic energy
energy lost = 0.5 * mv1^2 - 0.5 * mv2^2
energy lost = 0.5 * m(v1^2 - v2^2)
energy lost = 0.5 * 0.1905 * (8.223^2 - 6.369^2)
energy transfered to environment = 2.577 J
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