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6) Yau ride on an elevator that is moving with constantupward cale. The reading

ID: 1774294 • Letter: 6

Question

6) Yau ride on an elevator that is moving with constantupward cale. The reading on the scale is A) equal to your true weight, mg less than your true weight, mg C) more than your true weight, mg D) could be more or less than your true weight mg depending on the magsihude 7) You are standing in a moving bus and you suddenly move forward as the bus driver slems on t The force that causes you to move forward is Aj the force due to static friction between you and the floor of the bus ) the normal force due to your contact with the floor of the bs C) No force made you move forward- it was just your inertia s) A gar collides head-on with a fly. During the collision The acceleration of the car and the fly is the same B) The acceleration of the fly is greater than the acceleration of the car C) The acceleration of the car is greater than the acceleration of the fly 9) Two abjects, each of weight W, hang vertically connected by a spring scale as shown in the figure. The pulleys and the strings attached to the objects have negligible weight, and there is no appreciable friction /W in the pulleys. The scale reading tension in the string) is A) W B) more than 2W C) more than W, but not quite twice as much D) less than W 10) A 20-ton truck collides with a 1500-lb car and causes a lot of damage to the car. During the collision A) the force on the car due to the collision is much greater than the force on the truck B) the force on the truck due to the collision is exactly equal to the force on the car C) the force on the truck due to the colision is slightly greater than the force on the car 11) If the net force on a moving object is equal to zero, it will continue to move with constant velocity in a straight line B) stop immediately C) move with constant velocity in a circular orbit. D) gradually speed up until it reaches its terminal velocity E) slow down and eventually come to a stop.

Explanation / Answer

6. (C) more than your true weight, mg.

when elevator is accelerating upward, an extra downward psuedo force is acting on you (in elevator frame), which will give you net weight more than mg,

W = m(g+a) , where a is acceleration of elevator.

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