(13%) Problem 8: In the figure, three resistors are connected to a voltage sourc

Question

(13%) Problem 8: In the figure, three resistors are connected to a voltage source so that R2 and R3 are in parallel with one another and that combination is in series with 1.00 12.0 V R2 6.00 13 3.0 ©theexpertta.com Calculate 13 using the potential and resistances given in the figure Grade Summary Deductions Potential 0% 100% tan() | Submissions Attempts remaining: 5 cos) cotan)asin)acos0 atan) acotan)sinh0 coshOtanh cotanhO Sin per attempt) detailed view 0 END Degrees Radians BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0%_deduction per feedback

Explanation / Answer

As 6 Ohm and 13 Ohm are in parallel hence their net resistance is given by Rp = 6×13/(6+13) = 6×13/19 = 4.11 Ohm

Now this 4.11 Ohm is in series with 1.00 Ohm, so net resistance is

R = 4.11 + 1.00 = 5.11 Ohm,

So net current I = V/R = 12.0/5.11 = 2.35 A

This current will remain same in series hence potential drop across parallel combination is Vp = I Rp = 2.35 × 4.11 = 9.66 Volt

Now this potential drop will remain same in parallel

hence I3 = 9.66/13 = 0.74 A

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