A 9.5 cm diameter circular loop of wire is in a 0.92 T magnetic field. The loop

Question

A 9.5 cm diameter circular loop of wire is in a 0.92 T magnetic field. The loop is removed from the field in 0.15 s . Assume that the loop is perpendicular to the magnetic field.

Part A

What is the average induced emf?

Express your answer using two significant figures.

A 9.5 cm diameter circular loop of wire is in a 0.92 T magnetic field. The loop is removed from the field in 0.15 s . Assume that the loop is perpendicular to the magnetic field.

Part A

What is the average induced emf?

Express your answer using two significant figures.

Explanation / Answer

Diameter = 9.5 cm

So, radius, r = 9.5 / 2 = 4.75 cm = 0.0475 m.

Average induced emf = |dflux/dt|
= |d(BA)/dt|
= A * |dB/dt|
= pi*0.0475^2 * | (0 - 0.92) / 0.15 |
= 7.087 x 10^-2 x 6.13

= 0.435 V

In two significant figures the answer is 4.4 x 10^-1 V.

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