Practice Problem 21.4 SOLUTION Here we\'ll see that an emf can be induced by the

Question

Practice Problem 21.4 SOLUTION Here we'll see that an emf can be induced by the motion of the conductor in a static magnetic field. The U-shaped conductor in (Fiqure 1) lies perpendicular to a uniform magnetic field B with magnitude B 0.40T, directed into the page. We lay a metal rod with length L0.10m across the two arms of the conductor, forming a conducting loop, and move the rod to the right with constant speed u = 2.5m/s. What is the magnitude of the resulting emf? SET UP AND SOLVE The magnetic fux through the loop is changing because the area of the loop is increasing. During a time interval 1' the sliding rod moves a distance v1 and the area increases by AA-LuAt. Therefore, in time t, the magnetic flux through the loop increases by an amount 9a- AA-BLUM. The magnitude of the induced emf is -ADB/ = BLU. With the numerical values given, we find (0.40T)(0.10m)(2.5m/s) = 0.10V REFLECT We've found the magnitude of the emf but not the direction of the resulting induced current. Does the current flow clockwise or counterclockwise? Part A - Practice Problem: With the given magnetic field and rod length, what must the speed be if the induced emf has magnitude 0.71 V? Express your answer to three significant figures and include appropriate units alueUnits Figure of 1 Submit My Answers Give Up de Feedback Continue

Explanation / Answer

We know

Emf induced Is given by

E=B*v*l

Here

B=0.4 T

L=0.1 M

E=0.71

We got

v=17.75 m/s

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.