P2. Two cylindrical metal wires of length L = 2.00 m, and radius r 0.200 mm are
ID: 1774854 • Letter: P
Question
P2. Two cylindrical metal wires of length L = 2.00 m, and radius r 0.200 mm are attached to each other as shown in the figure below. The first wire is made of a metal with resistivityPs=1.69x10"Qm and the second one of metal with resistivity Ps-2.75 x10-8 -m. A potential difference V = 300 mV is applied to the far ends of the two wires as shown in the figure below. Neglect any possible contact resistance between the wires. a. (2) Calculate the resistance Ri of the 1st wire. b. (2) Calculate the resistance R2 of the 2nd wire. c. (4) What is the current i through the wires? d. (4) What is the total power P dissipated in the two wires? e. (3) What is the magnitude of the current density in the 1st wire? f. (3) What is the magnitude of the current density J2 in the 2nd wire? The carrier (electron) charge density (ne) in the 1st wire is three times that of the 2nd wire, (ne)y-3.00x(ne)2, and the left hand side of the arrangement is at higher potential. g. (4) Calculate the magnitude of the drift velocity va2 of electrons in the 2nd wire if its h. (3) Indicate on the figure directions of the current i and the drift velocities vai and vaz. value in the 1st wire is vdi = 2.50x10-6 m/s.Explanation / Answer
Solving 1st 4 parts
(a) R1=resistivity*length/area=0.268 ohm
(b)similarly
R2=0.438 ohm
(c)current=V/(R1+R2)=0.425 A
(d)power dissipated=V*I=0.127 W
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