A 0.060kg tennis ball, moving with a speed of 5.46 m/s, has a head on collision

Question

A 0.060kg tennis ball, moving with a speed of 5.46 m/s, has a head on collision with a 0.080kg ball initially moving in the same direction at a speed of 3.72 m/s. Assume that the collision is perfectly elastic. Part A: Determine the speed of the 0.060kg ball after the collision. Part B: Determine the direction of the velocity of the 0.060kg ball after the collision. A-In the direction of the initial velocity or B-In the direction opposite to the initial velocity Part C: Determine the speed of the 0.080kg ball after the collision. Part D: Determine the direction of the velocity of the 0.080kg ball after the collision. A-In the direction of the initial velocity or B-In the direction opposite to the initial velocity

A 0.060kg tennis ball, moving with a speed of 5.46 m/s, has a head on collision with a 0.080kg ball initially moving in the same direction at a speed of 3.72 m/s. Assume that the collision is perfectly elastic. Part A: Determine the speed of the 0.060kg ball after the collision. Part B: Determine the direction of the velocity of the 0.060kg ball after the collision. A-In the direction of the initial velocity or B-In the direction opposite to the initial velocity Part C: Determine the speed of the 0.080kg ball after the collision. Part D: Determine the direction of the velocity of the 0.080kg ball after the collision. A-In the direction of the initial velocity or B-In the direction opposite to the initial velocity

Part A: Determine the speed of the 0.060kg ball after the collision. Part B: Determine the direction of the velocity of the 0.060kg ball after the collision. A-In the direction of the initial velocity or B-In the direction opposite to the initial velocity Part C: Determine the speed of the 0.080kg ball after the collision. Part D: Determine the direction of the velocity of the 0.080kg ball after the collision. A-In the direction of the initial velocity or B-In the direction opposite to the initial velocity

Explanation / Answer

for elastic colliison,

velocity of approach = velocity of separation

(5.46 - 3.72) = V - v

V = 1.74 + v

Applying momentum conservation,

0.060 x5.46 + 0.080 x3.72 = 0.060v + 0.080V

6v + 8(1.74 + v) = 62.52

v = 3.47 m/s

(A) v = 3.47 m/s

(B) A - in the direction of initial

(C) V = v + 1.74 = 5.21 m/s

(D) B. in the opposite direction

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