1. 1 points BauerPhys1 3.P.033. My Notes Ask Your Teacher What is the magnitude
ID: 1775098 • Letter: 1
Question
1. 1 points BauerPhys1 3.P.033. My Notes Ask Your Teacher What is the magnitude of an object's average velocity if an object moves from a point with coordinates x = 1.5 m, y =-2.5 m to a point with coordinates x = 5.1 m, y =-8.9 m in a time interval of 2.3 s? 2. -12 points BauerPhys1 3.P.034 My Notes Ask Your Teacher A man in search of his dog drives first 11 mi northeast, then 41 mi straight south, and finally 7 mi in a direction 30° north of west. What are the magnitude and direction of his resultant displacement? magnitude o south of east 3. 2 points BauerPhys1 4.P.023. My Notes Ask Your Teacher The gravitational acceleration on the Moon is a sixth of that on Earth. The weight of a rock is 9.20 N on Earth. (a) What is the weight of the rock on the Moon? (b) What is the mass of the rock?Explanation / Answer
1) initial position vector of object=1.5i-2.5j
Final position vector of object=5.1i-8.9j
Displacement vector = (5.1i-8.9j)-(1.5i-2.5j) = 3.6i-6.4j
Time taken = 2.3 seconds
Velocity = (3.6i-6.4j)/2.3=1.565i-2.783j m/s
Magnitude of velocity = sqrt(1.5652+2.7832)=3.193 m/s
2)x coordinate of man after travelling 11 mi NorthEast= 11cos45=7.778 mi
y coordinate of man after travelling 11 mi NorthEast = 11sin45=7.778 mi
x coordinate of man after travelling 41 mi South = 7.778 mi
y coordinate of man after travelling 41 mi South = 7.778-41=-33.222 mi
x coordinate of man after travelling 7 mi 30o North of West = 7.778-7cos30=1.716 mi
y coordinate of man after travelling 7 mi 30o North of West= -33.222+7sin30=-29.722 mi
Magnitude of resultant displacement =sqrt(1.7162+29.7222)=29.77 mi
Direction of resultant displacement = tan-1(29.722/1.716)=86.7o South of East
3)a)weight of rock on Earth=9.2 N
Weight of rock on Moon = 9.2/6=1.533 N
b)Mass of rock = 9.2/9.8=0.939 kg
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