Nina ties a 0.055 kg rubber stopper to one end of a string and the other end of

Question

Nina ties a 0.055 kg rubber stopper to one end of a string and the other end of the string passes through a frictionless tube and is tied to a 0.85 kg second mass. Holding the tube, she twirls the rubber stopper in a horizontal circle above her dead so that the second mass remains in equilibrium. If the stopper moves in a circle with a radius of 0.65 m, how fast is it moving? Nina ties a 0.055 kg rubber stopper to one end of a string and the other end of the string passes through a frictionless tube and is tied to a 0.85 kg second mass. Holding the tube, she twirls the rubber stopper in a horizontal circle above her dead so that the second mass remains in equilibrium. If the stopper moves in a circle with a radius of 0.65 m, how fast is it moving?

Explanation / Answer

for the rotating mass

Tension ine string T = centripetal force = m1*v^2/r

for the hanging mass m2

along vertical in equilibrium Fnet = 0

T - m2*g = 0

m1*v^2/r = m2*g

speed v = sqrt(r*(m2/m1)*g)

speed = v = sqrt(0.65*(0.85/0.055)*9.8)

speed v = 9.92 m/s <<<---------ANSWER

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