Online HW 08 Begin Date: 10282017 5:00:00 PMue ate: 11/102017 5:0000 PM End Date

Question

Online HW 08 Begin Date: 10282017 5:00:00 PMue ate: 11/102017 5:0000 PM End Date: 11/10/2017 500:00 PM quick stop, a car decelerates at 78 m/s2.Assume the forward motion of the car corresponds to a positive direction for the rotation of the tires (and that they do not slip on the pavement). A0.25m a%- 91 rad/s for u v, 20% Part (a) pavement? what is the angular acceleration of its tires in rad/s, assuming they have a radius of 0.25 m and do not slip on the Grade Summary Dedactioes Potential tatus 97% ompleted pleted Amempts remaining: 4 per attemp) cotano asinacos0 atan0 acotan sinh0 1 2 3 Hint Feedback 2 20% Part (c) How long does the car take to stop completely in seconds? 20% Part (d) what distance does the car travel in this time in meters? 20% Part (e) what was the car's initial speed in m/s?

Explanation / Answer

part a:

= a / r

= 7.8m/s² / 0.25m

= 31.2 rad/s²

Part b:

= ² / 2

= (91rad/s)² / 62.4rad/s²

= 132.708333 rads
= 132.708333 / 2 = 21.13 revs

part c:

t = /

t = 91rad/s / 31.2rad/s²

t = 2.9 seconds

part d)

s = *r

s = 132rads * 0.25m = 33.2 meters

part e)

v = *r

v = 91rad/s * 0.25m = 22.75 m/s

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